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Exam Code: 1Z0-047
Exam Name: Oracle (Oracle Database SQL Expert)
One year free update, No help, Full refund!
Total Q&A: 260 Questions and Answers
Last Update: 2014-01-16

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NO.1 EMPDET is an external table containing the columns EMPNO and ENAME. Which command would
work in relation to the EMPDET table?
A.UPDATE empdet SET ename = 'Amit' WHERE empno = 1234;
B.DELETE FROM empdet WHERE ename LIKE 'J%';
C.CREATE VIEW empvu AS SELECT * FROM empdept;
D.CREATE INDEX empdet_idx ON empdet(empno);
Answer:C

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NO.2 Evaluate the following CREATE SEQUENCE statement: CREATE SEQUENCE seq1 START WITH 100
INCREMENT BY 10 MAXVALUE 200 CYCLE NOCACHE; The sequence SEQ1 has generated numbers
up to the maximum limit of 200. You issue the following SQL statement: SELECT seq1.nextval FROM
dual; What is displayed by the SELECT statement?
A.1
B.10
C.100
D.an error
Answer:A

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NO.3 View the Exhibit and examine PRODUCTS and ORDER_ITEMS tables. You executed the following
query to display PRODUCT_NAME and the number of times the product has been ordered: SELECT
p.product_name, i.item_cnt FROM (SELECT product_id, COUNT (*) item_cnt FROM order_items
GROUP BY product_id) i RIGHT OUTER JOIN products p ON i.product_id = p.product_id; What would
happen when the above statement is executed?
A.The statement would execute successfully to produce the required output.
B.The statement would not execute because inline views and outer joins cannot be used together.
C.The statement would not execute because the ITEM_CNT alias cannot be displayed in the outer query.
D.The statement would not execute because the GROUP BY clause cannot be used in the inline view.
Answer:A

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NO.4 View the Exhibit and examine the data in ORDERS and ORDER_ITEMS tables. You need to create a
view that displays the ORDER ID, ORDER_DATE, and the total number of items in each order. Which
CREATE VIEW statement would create the view successfully?
A.CREATE OR REPLACE VIEW ord_vu (order_id,order_date) AS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id) "NO OF ITEMS" FROM orders o JOIN order_items i ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
B.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
"NO OF ITEMS" FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY
o.order_id,o.order_date;
C.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY o.order_id,o.order_date;
D.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)||'
NO OF ITEMS' FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY
o.order_id,o.order_date WITH CHECK OPTION;
Answer:B

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NO.5 View the Exhibit and examine the descriptions of ORDER_ITEMS and ORDERS tables. You want to
display the CUSTOMER_ID, PRODUCT_ID, and total (UNIT_PRICE multiplied by QUANTITY) for the
order placed. You also want to display the subtotals for a CUSTOMER_ID as well as for a PRODUCT_ID
for the last six months. Which SQL statement would you execute to get the desired output?
A.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id,oi.product_id) WHERE
MONTHS_BETWEEN(order_date, SYSDATE) <= 6;
B.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id,oi.product_id) HAVING
MONTHS_BETWEEN(order_date, SYSDATE) <= 6;
C.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id, oi.product_id) WHERE
MONTHS_BETWEEN(order_date, SYSDATE) >= 6;
D.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id WHERE MONTHS_BETWEEN(order_date, SYSDATE) <= 6
GROUP BY ROLLUP (o.customer_id, oi.product_id) ;
Answer:D

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NO.6 Which two statements are true? (Choose two.)
A.The USER_SYNONYMS view can provide information about private synonyms.
B.The user SYSTEM owns all the base tables and user-accessible views of the data dictionary.
C.All the dynamic performance views prefixed with V$ are accessible to all the database users.
D.The USER_OBJECTS view can provide information about the tables and views created by the user
only.
E.DICTIONARY is a view that contains the names of all the data dictionary views that the user can access.
Answer:A E

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NO.7 View the Exhibit and examine the description of the ORDERS table. Which two WHERE clause
conditions demonstrate the correct usage of conversion functions? (Choose two.)
A.WHERE order_date > TO_DATE('JUL 10 2006','MON DD YYYY')
B.WHERE TO_CHAR(order_date,'MON DD YYYY') = 'JAN 20 2003'
C.WHERE order_date > TO_CHAR(ADD_MONTHS(SYSDATE,6),'MON DD YYYY')
D.WHERE order_date IN ( TO_DATE('Oct 21 2003','Mon DD YYYY'), TO_CHAR('NOV 21 2003','Mon DD
YYYY') )
Answer:A B

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NO.8 View the Exhibit and examine the structure of the EMPLOYEES table. You want to retrieve hierarchical
data of the employees using the top-down hierarchy. Which SQL clause would let you choose the
direction to walk through the hierarchy tree?
A.WHERE
B.HAVING
C.GROUP BY
D.START WITH
E.CONNECT BY PRIOR
Answer:E

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NO.9 Evaluate the following SQL statement: ALTER TABLE hr.emp SET UNUSED (mgr_id); Which
statement is true regarding the effect of the above SQL statement?
A.Any synonym existing on the EMP table would have to be re-created.
B.Any constraints defined on the MGR_ID column would be removed by the above command.
C.Any views created on the EMP table that include the MGR_ID column would have to be dropped and
re-created.
D.Any index created on the MGR_ID column would continue to exist until the DROP UNUSED
COLUMNS command is executed.
Answer:B

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NO.10 View the Exhibit and examine the description of the CUSTOMERS table. You want to add a constraint
on the CUST_FIRST_NAME column of the CUSTOMERS table so that the value inserted in the column
does not have numbers. Which SQL statement would you use to accomplish the task?
A.ALTER TABLE CUSTOMERS ADD CONSTRAINT cust_f_name
CHECK(REGEXP_LIKE(cust_first_name,'